Chapter 12 - Homework Answers (Equilibrium)
Chapter 12 Homework
Answers
When the following equation
is balanced using the smallest possible integers, what is the exponent of N2O in the reaction quotient expression?
N2O + H2 ó NH3 + H2O
Its
balanced equation is
(1)N2O
+ 4H2 ó 2NH3 + H2O
there is
a 1 in front of the N2O when it is balanced therefore the exponent
is 1
N2O(g)
+ H2(g) ó
NH3(g) + H2O(g)
____1_____
In a 1.0 L vessel, at 298 K, 0.761 M A
(g) and 0.916 M B (g) react to form 0.503 M C (g). What is the value of the
equilibrium constant for this reaction at 298K?
A (g) + B (g) ↔ C (g)
A (g) + B (g) ↔ C (g)
a.
|
4.72
|
b.
|
0.212
|
c.
|
0.722
|
d.
|
0.00242
|
e.
|
1.24
|
Take C
and subtract it from A & B, now A=.258 and B=.413
Use C/AB = Products/Reactants = 4.72
In a 1.0 L vessel, at 298 K, 0.0323 mol
COCl2 (g)
is added. What is the equilibrium concentration of CO
if Kc = 1.2 x 103 at this temperature?
if Kc = 1.2 x 103 at this temperature?
CO (g) +
Cl2 (g) ↔
COCl2 (g)
a.
|
0.0000269
|
b.
|
0.000475
|
c.
|
0.000932
|
d.
|
0.000240
|
e.
|
0.0485
|
Since we
start out with the product we have to work our way backerds.
[C] =
0.0323-x because it’s becoming equalized with [A]&[B]
[A] and
[B] are (0+x) respectively.
Make
equation [C]/[A][B] = à 0.0323-x/(0+x)(0+x) = 1200 Solve for x
and you get…
0.000475 maybe book made error?
In a 1.0 L vessel, at 698 K, 0.844 M H2 (g)
and 0.844 M I2 (g)
are combined. What is the concentration of HI (g) at equilibrium? Kc =
54.3 at 698 K.
H2 (g) +
I2 (g) ↔
2 HI (g)
a.
|
1.33
|
b.
|
1.69
|
c.
|
0.198
|
d.
|
0.664
|
e.
|
1.25
|
H2 + I2 <-------------> 2HI
initially....
0.844 + 0.844 <------------> 0
at equilibrium...
(0.844 - x ) + ( 0.844 - x ) <------------> 2x
conc. of H2 at equilibrium = 0.844-x
conc. of I2 at equilibrium = 0.844 - x
conc. of HI at equilibrium = 2x
Kc = [HI]^2 / [H2][I2] = 2x^2 / ( 0.844 - x ) ( 0.844 - x )
54.3 = 4x^2 / (0.844 -x)^2
54.3 = 4x^2 / ( 0.844^2 + x^2 - 2 X 0.844x)
54.3 = 4x^2 / ( 0.712 + x^2 - 1.688x )
54.3 ( 0.712 + x^2 - 1.688x ) = 4x^2
38.662 + 54.3x^2 - 91.658x = 4x^2
54.3x^2 - 4x^2 - 91.658x + 38.662 = 0
50.3x^2 - 91.658x + 38.662 = 0 ...
Solve the
quadratic equation
x = 0.663 and x = 1.159
as x cant be greater than 0.844 as otherwise concentration will be negative
so conc of HI at equilibrium = 2x = 2 X 0.663 = 1.33 M
x = 0.663 and x = 1.159
as x cant be greater than 0.844 as otherwise concentration will be negative
so conc of HI at equilibrium = 2x = 2 X 0.663 = 1.33 M
If 1.00 mole of PCl3 and
1.00 mole of Cl2 are
placed in a 5.00-L container, the following equilibrium is reached.
PCl3 (g) +
Cl2 (g) ⇔ PCl5 (g) Kc = 10.0 at the temperature maintained.
What is the
equilibrium concentration of [PCl3] in mol/L? .2
is from mol per L, 1/5 mol/L
a.
|
0.12
|
b.
|
0.13
|
c.
|
0.14
|
d.
|
0.11
|
e.
|
0.10
|
_________________PCl5<------>PCl3__+_Cl...
Initial concentration_0M_______.2M_____.2M
Reaction__________+x________-x_______-x
Equilibrium________ x________.2-x_____.2-x
Now you can plug your equilibrium values into your equilibrium equations.
10 = x/(.2-x)(.2-x)
10 = x/(.04 - .4x + x^2)
then .4 -4x + 10x^2 = x .4 - 5x + 10x^2 = 0
Now that you can use the quadratic equation to solve for x.
You should get x = .4 and .1
Now if you use .4 for x, you will have negative values for your PCl3 and Cl2 which is impossible.
So x has to be .1
Now solve for your concentration of PCl3
PCl3 = .2 - x
.2 - .1 = .1M
The solubility of lead(II) chloride is
0.45 g/100 mL of solution. What is the Ksp of
PbCl2?
a.
|
4.9 × 10¯2
|
b.
|
1.7 × 10¯5
|
c.
|
8.5 × 10¯6
|
d.
|
4.2 × 10¯6
|
e.
|
< 1.0 × 10¯6
|
First,
convert g/mL to mol/L by doing the table (YOU MUST DO THE TABLE)
Then
split up the Pb and the Cl2 and balance: PbCl2àPb2+ + 2Cl-
Set up the equation like this Ksp = [Pb2+][Cl-]2
. Now apply mol/L to each respectively.
For [Pb2+]
= 1(0.0162 mol/L)
For [Cl-]2 = 2(0.0162 mol/L)2
And solve (0.0162)*(2(0.0162))^2 = 0.0000169 mol/L OR 1.7 * 10^-5 mol/L
Which of the following substances has
the greatest solubility in water?
a.
|
PbI2, Ksp = 7.9 × 10¯9
|
b.
|
BaF2, Ksp = 1.5 × 10¯6
|
c.
|
Ca(OH)2, Ksp = 6.5 × 10¯6
|
d.
|
Zn(IO3)2, Ksp =
3.9 × 10¯6
|
e.
|
Ag2SO4, Ksp = 1.5 × 10¯5
|
What is the pH of a 0.0100 M sodium benzoate solution? Kb (C7H5O2¯) = 1.5 × 10¯10
a.
|
0.38
|
b.
|
5.91
|
c.
|
8.09
|
d.
|
9.82
|
e.
|
13.62
|
x=sqrt((0.01M) * (1.5 * 10^-10)) Then take the –log of the answer (.000001225)
And you
get 5.912 (WHICH IS NOT THE ANSWER) this is only the pOH.
To get
the pH take 14 - 5.912 = 8.0881
Aqueous solutions of phosphoric acid
and sodium nitrite are combined, and the following equilibrium is established.
H3PO4(aq) + NO2¯(aq) ó H2PO4¯(aq) + HNO2(aq)
The equilibrium constant Kc for this reaction is greater than one. Based on this information, which of the following statements is correct?
H3PO4(aq) + NO2¯(aq) ó H2PO4¯(aq) + HNO2(aq)
The equilibrium constant Kc for this reaction is greater than one. Based on this information, which of the following statements is correct?
a.
|
The
nitrite anion is a weaker base than the dihydrogen phosphate anion.
|
b.
|
Nitrous
acid is a weaker acid than water.
|
c.
|
Phosphoric
acid is a weaker acid than nitrous acid.
|
d.
|
The
dihydrogen phosphate anion is a stronger acid than nitrous acid.
|
e.
|
Phosphoric acid is a stronger acid than
nitrous acid.
|
If NaCl is added to a saturated
solution of AgCl, the equilibrium will shift back towards the reactants; and
the solubility of AgCl will decrease.
1.
|
True
|
2.
|
False
|
Well if
AgCl is already saturated then yeah.
What would be the effect of decreasing the temperature on the following reaction?
C2H2(g) + H2O(g) <=> CH3CHO(g) DHrxn = -15 1 kJ
a.
|
[CH3CHO] would
increase
|
b.
|
[CH3CHO] would decrease
|
c.
|
[CH3CHO] would stay the same
|
The equilibrium constant for the
following reaction is given. Assuming that the forward and reverse reactions
can be written as elementary steps, which statement below is true for this
reaction at equilibrium?
A ⇔ B + C Kc =
150
a.
|
The rate
constants for the forward and reverse reactions are identical at equilibrium.
|
b.
|
The rate
constant for the reverse reaction is 150 times greater than that for the forward
reaction.
|
c.
|
The rate
constant for the forward reaction is smaller than that for the reverse
reaction.
|
d.
|
The rate constant for the forward
reaction is 150 times greater than that for the reverse reaction.
|
e.
|
The rate
constants for this reaction cannot be determined based on the equilibrium
constant.
|
The term "strong acid" refers
to any acid of 0.100 M concentration or higher.
1.
|
True
|
2.
|
False
|
A strong
acid is one that completely dissociates in water or a solution.
At a certain temperature, the equilibrium mixture of the reaction PCl5 (g) ⇔ PCl3 + Cl2 (g) has PCl5 = 1.50 atm. PCl3 = 0.10 atm and PCl2= 7.50 atm Calculate the value of Kp at this temperature.
a.
|
0.77
|
b.
|
0.50
|
c.
|
2.0
|
d.
|
1.3
|
e.
|
1.0
|
Assuming Cl2 is meant to be PCl2 then Kp is a normal equilibrium problem.
(0.10 * 7.50)/1.5 Products over reactants.
An equilibrium mixture of NO (g), O2 (g)
and NO2 (g)
is allowed to expand from 1.0 L to 2.0 L at a constant temperature.
2 NO (g) + O2 (g) ⇔ 2 NO2 (g)
Which of the following statements is correct?
NO CLUE
a.
|
Concentrations of all three gases are unchanged.
|
b.
|
The value of Kp would decrease.
|
c.
|
The number of moles of NO2 would
increase.
|
d.
|
The number of
moles of O2 would
increase.
|
e.
|
The number of moles of all three gases are unchanged.
|
For the reaction: H2 +
Br2 ⇔
2 HBr, Kc =
7.5 × 102 at
a certain temperature.
1.00 mole HBr is placed in 5.0 L flask
at a certain temperature. What is the concentration of HBr at equilibrium?
a.
|
0.19
|
b.
|
0.81
|
c.
|
0.01
|
d.
|
0.94
|
e.
|
0.03
|
Do the ICE table and REMEMBER HBR IS SQUARED.
For the reaction: H2 + Br2 ⇔ 2 HBr, Kc = 7.5 × 102 at a certain temperature.
If 1 mole each of H2 and Br2 are placed in 1 L flask, what is the concentration of H2 at equilibrium?
a.
|
0.46
|
b.
|
0.04
|
c.
|
0.93
|
d.
|
0.96
|
e.
|
0.07
|
What is the molar solubility of CaF2 (Ksp =
3.9 ∗ 10-11)?
1.
|
2.14 ∗ 10-4 M
|
2.
|
6.24 ∗ 10-6 M
|
3.
|
9.27 ∗ 10-5 M
|
4.
|
4.41 ∗ 10-6 M
|
The lower the pH of a weak acid, the:
1.
|
higher
the dissolved H2(g) concentration.
|
2.
|
none of
the above
|
3.
|
higher the Ka of the acid.
|
4.
|
higher
the concentration of the weak acid.
|
A solution is prepared by adding 0.10
mol of sodium fluoride, NaF, to 1.00 L of water. Which statement about the
solution is correct?
a.
|
The solution is basic.
|
b.
|
The
solution is neutral.
|
c.
|
The
solution is acidic.
|
d.
|
The concentrations
of fluoride ions and sodium ions will be identical.
|
e.
|
The
concentration of fluoride ions will be greater than the concentration of
sodium ions.
|
In a dynamic equilibrium the rates of
the forward and reverse reactions go to zero once the equilibrium is reached. Dynamic means it’s going back and
forth to an extent “forever”
1.
|
False
|
2.
|
True
|
In a dynamic equilibrium:
1.
|
the rate
of the forward reaction goes to zero
|
2.
|
the rates of the forward and reverse
reactions become equal
|
3.
|
the reaction
begins to favor the reverse direction
|
4.
|
the rate
of the forward and reverse reactions go to zero
|
If a reaction is in a state where Q > K,
1.
|
the rate of the
reaction will always double.
|
2.
|
more products will
form.
|
3.
|
the reaction will
remain in a steady-state.
|
4.
|
more reactants will form.
|
The synthesis of the pesticide thionyl
chloride (OSCl2)
proceeds according to:
SO3(g) + SCl2(l) ó OSCl2(l) + SO2(g)
If ΔG0 = -106 kJ/mol for this reaction at 298K, what is the Keq at this temperature? Recall: R = 8.314 J mol-1 K-1.
SO3(g) + SCl2(l) ó OSCl2(l) + SO2(g)
If ΔG0 = -106 kJ/mol for this reaction at 298K, what is the Keq at this temperature? Recall: R = 8.314 J mol-1 K-1.
1.
|
3.81 ∗ 1018
|
2.
|
7.21 ∗ 1012
|
3.
|
3.50 ∗ 1014
|
4.
|
1.19 ∗ 1020
|
Write the ion product expression for
calcium phosphate, Ca3(PO4)2.
a.
|
[Ca2+][PO43-]
|
b.
|
[Ca2+]2[PO43-]3
|
c.
|
[Ca2+]3[PO43-]2 <<<<------ This One
|
d.
|
[Ca2+][PO43-]
[Ca3(PO4)2
|
e.
|
None of these choices is correct.
|
Write the ion product expression for
silver sulfide, Ag2S.
a.
|
[Ag+][S2-]
|
b.
|
[Ag+][S2-]2
|
c.
|
[Ag+]2[S2-]
[Ag2S(s)]
|
d.
|
1
.
[Ag+][S2-]2
|
e.
|
[Ag+]2[S2-]
|
The lower the pH of a weak acid, the:
1.
|
higher the Ka of the acid.
|
2.
|
higher
the dissolved H2(g) concentration.
|
3.
|
higher
the concentration of the weak acid.
|
4.
|
none of
the above
|
Consider the following exothermic
reaction:
N2 (g) + 3 H2 (g) ⇔ 2 NH3 (g)
N2 (g) + 3 H2 (g) ⇔ 2 NH3 (g)
Which
of the following changes would not increase the amount of NH3 produced
from given quantities of
N2 and H2?
N2 and H2?
a.
|
an
increase in P
|
b.
|
an increase in T
|
c.
|
a
decrease in V
|
d.
|
removing
some NH3 and
reestablishing equilibrium
|
e.
|
none of
these
|
Sodium bicarbonate undergoes thermal
decomposition according to
2
NaHCO3(s) ó Na2CO3(s) + CO2(g) + H2O(g)
What
happens when some NaHCO3 is added
a.
|
[CO2] increases
|
b.
|
[CO2] decreases
|
c.
|
[CO2] stays the
same
|
Sodium bicarbonate undergoes thermal decomposition
according to
2
NaHCO3(s) ó Na2CO3(s) + CO2(g) + H2O(g)
What
happens when some dry ice (CO2(s)) is added and
converts partly to CO2(g)?
a.
|
[H2O] stays the same
|
b.
|
[H2O] decreases
|
c.
|
[H2O] increases
|
Products appear in the numerator of the
reaction quotient
1.
|
False
|
2.
|
True
|
Kp for
the reaction H2 (g)
+ I2 (g)
⇔ 2 HI(g) is 54.3 at 698°C. What is the
value of Kc at
this temperature?
(R = 0.0821 L atm/mol K)
a.
|
85.6
|
b.
|
1.8 × 10−2
|
c.
|
2.3 × 10−4
|
d.
|
4.33 × 103
|
e.
|
54.3
|
Which of the following substances has
the greatest solubility in water?
a.
|
Ba(IO3)2, Ksp = 1.5 × 10¯9
|
b.
|
PbF2, Ksp = 3.6 × 10¯8
|
c.
|
SrSO4, Ksp =
3.2 × 10¯7
|
d.
|
CuCl, Ksp = 1.9 × 10¯7
|
e.
|
CdS, Ksp = 1.0 × 10¯24
|
What is the pH of a 0.0250 M pyridine
solution? (Kb =
1.5 ∗ 10-9)?
1.
|
13.1
|
2.
|
8.79
|
3.
|
5.21
|
4.
|
4.72
|
Calculate the solubility of zinc hydroxide, Zn(OH)2, in 1.00 M NaOH.
Ksp = 3.0 × 10¯16 for Zn(OH)2, Kf = 3.0 × 1015 for Zn(OH)42¯
a.
|
0.60 M
|
b.
|
0.52 M
|
c.
|
0.37 M
|
d.
|
0.32 M
|
e.
|
0.24 M
|
Sodium bicarbonate undergoes thermal
decomposition according to
2
NaHCO3(s) ó Na2CO3(s) + CO2(g) + H2O(g)
What happens when 0.20 atm of argon gas is added
a.
|
[CO2] stays the
same
|
b.
|
[CO2] decreases
|
c.
|
[CO2] increases
|
Which of following species is
amphoteric?
1.
|
C4H10
|
2.
|
NaOH
|
3.
|
H2O
|
4.
|
H2SO4
|
Because, it can act as an acid and a base by either giving or
receiving a hydrogen atom.
If the equilibrium concentrations found in the reaction:
2 A(g) + B(g) ⇔
2 C(g),
are A = 0.35 M, B = 0.32 M, and C = 0.46 M. Calculate Kc as a decimal number (e.g., 1.234) with 3
decimal places and do not include units.
___0.185___
The higher the Ksp of
the salt, the less soluble the salt.
1.
|
False
|
2.
|
True
|
Calculate the solubility of silver
oxalate, Ag2C2O4, in pure water. Ksp =
1.0 × 10¯11
a.
|
1.4 × 10¯4 M
|
b.
|
5.4 × 10¯5 M
|
c.
|
8.2 × 10¯5 M
|
d.
|
3.2 × 10¯6 M
|
e.
|
2.5 × 10¯12 M
|
What is the pH of a 0.165 M CH3COOH solution (Ka =
1.75 ∗ 10-5)?
1.
|
2.770
|
2.
|
8.474
|
3.
|
3.188
|
4.
|
5.721
|
What is the pH of a 0.050 M
triethylamine, (C2H5)3N, solution?
Kb for triethylamine is 5.3 × 10¯4.
Kb for triethylamine is 5.3 × 10¯4.
a.
|
11.69
|
b.
|
5.32
|
c.
|
< 2.0
|
d.
|
2.31
|
e.
|
8.68
|
The equilibrium constant for the
following reaction is given. Assuming that the forward and reverse reactions
can be written as elementary steps, which statement below is true for this
reaction at equilibrium?
A ⇔ B + C Kc = 150
A ⇔ B + C Kc = 150
a.
|
The rate
constants for the forward and reverse reactions are identical at equilibrium.
|
b.
|
The rate constant for the forward
reaction is 150 times greater than that for the reverse reaction.
|
c.
|
The rate
constant for the reverse reaction is 150 times greater than that for the
forward reaction.
|
d.
|
The rate
constant for the forward reaction is smaller than that for the reverse
reaction.
|
e.
|
The rate
constants for this reaction cannot be determined based on the equilibrium
constant.
|
Which Keq value
indicates a reaction most favoring the formation of products?
1.
|
K = 1.7 ∗ 10-6
|
2.
|
K = 4.99 ∗ 106
|
3.
|
All these
Keq favor
reactants
|
4.
|
K = 5.31 ∗ 103
|
5.
|
K = 8.2 ∗ 10-3
|
Determine the value of Kc for
the following reaction given the Kp.
CO (g) + Cl2 (g) ⇔ COCl2 (g) Kp = 15.0 at 300°C (R = 0.0821
L•atm/molK)
a.
|
706
|
b.
|
1.42 × 10−3
|
c.
|
0.319
|
d.
|
369
|
e.
|
3.14
|
Use the following information to calculate the solubility
product constant, Ksp, for PbCl2. A saturated solution of PbCl2 in
water was prepared and filtered. From the filtrate, 1.0 L was measured out into
a beaker and evaporated to dryness. The solid PbCl2 residue recovered in the beaker amounted to
0.0162 moles.
a.
|
Ksp = 6.9 × 10¯8
|
b.
|
Ksp = 4.3 × 10¯6
|
c.
|
Ksp =
1.7 × 10¯5
|
d.
|
Ksp = 2.6 × 10¯4
|
e.
|
Ksp = 3.2 × 10¯2
|
Consider the solubility of BaSO4. If Ba(NO3)2 is
added to the solution, the solubility of the barium sulfate:
1.
|
is
unaffected
|
2.
|
is moot
because barium sulfate is a strong electrolyte
|
3.
|
increases
|
4.
|
decreases
|
Given the reaction shown
below at equilibrium, how will addition of 0.10 M K3PO4 solution
affect the equilibrium? Answer r for shift
to the right, l for shift to the left or n for
no change.
Ca3(PO4)2(s) ó 3Ca2+(aq) + 2PO43-(aq)
Ca3(PO4)2(s) ó 3Ca2+(aq) + 2PO43-(aq)
____L___
Which of following species is a
Brønsted-Lowry base?
1.
|
C4H10
|
2.
|
CaCl2
|
3.
|
NaOH
|
4.
|
H2SO4
|
A lab technician adds 0.015 mol of KOH
to 1.00 L of 0.0010 M Ca(NO3)2. Ksp =
6.5 × 10¯6 for
Ca(OH)2.
Which of the following statements is correct?
a.
|
Calcium
hydroxide precipitates until the solution is saturated.
|
b.
|
The solution is unsaturated and no
precipitate forms.
|
c.
|
The
concentration of calcium ions is reduced by the addition of the hydroxide
ions.
|
d.
|
One must
know Ksp for
calcium nitrate to make meaningful predictions on this system.
|
e.
|
The
presence of KOH will raise the solubility of Ca(NO3)2.
|
Picric acid has been used in the
leather industry and in etching copper. However, its laboratory use has been
restricted because it dehydrates on standing and can become shock sensitive. It
has an acid dissociation constant of 0.42. What is the [H3O+] for a 0.20 M
solution of picric acid?
a.
|
0.022 M
|
b.
|
0.052 M
|
c.
|
0.15 M
|
d.
|
0.29 M
|
e.
|
None of
these choices is correct.
|
Consider the dissolution of MnS in
water (Ksp =
3.0 × 10¯14).
MnS(s) + H2O(l) ó Mn2+(aq) + HS¯(aq) + OH¯(aq)
How is the solubility of manganese(II) sulfide affected by the addition of aqueous potassium hydroxide to the system?
MnS(s) + H2O(l) ó Mn2+(aq) + HS¯(aq) + OH¯(aq)
How is the solubility of manganese(II) sulfide affected by the addition of aqueous potassium hydroxide to the system?
a.
|
The
solubility will be unchanged.
|
b.
|
The solubility will decrease.
|
c.
|
The
solubility will increase.
|
d.
|
The
amount of KOH added must be known before its effect can be predicted.
|
e.
|
The pKa of
H2S is needed before a reliable prediction can be
made.
|
The term "strong acid" refers
to any acid of 0.100 M concentration or higher.
1.
|
False
|
2.
|
True
|
For the system 2A (g) + B( g) ⇔
2C (g), if the initial concentration of pure C is 1.00 M, the equilibrium
concentration is 0.40 M. What is the value of Kc for
the equilibrium as written?
a.
|
0.67
|
b.
|
2.2
|
c.
|
1.5
|
d.
|
5.0
|
e.
|
0.45
|
Hydroxylamine, HONH2, readily forms salts
such as hydroxylamine hydrochloride which are used as antioxidants in soaps.
Hydroxylamine has Kb of
9.1 × 10¯9.
What is the pH of a 0.025 M HONH2 solution?
1.
|
4.82
|
2.
|
9.18
|
3.
|
11.10
|
4.
|
2.90
|
5.
|
9.91
|
Which of these best describe the
direction the following reaction (in a 5.0 L flask) will proceed if more
calcium oxide is added to the system?
CaCO3 (s) ⇔ CaO (s) + CO2 (g) Kp = 1.9 x 10−23
CaCO3 (s) ⇔ CaO (s) + CO2 (g) Kp = 1.9 x 10−23
a.
|
to the
right
|
b.
|
to the
left
|
c.
|
The equilibrium position will not shift
because calcium oxide is a solid.
|
d.
|
The
equilibrium constant gets smaller to reflect the added calcium oxide.
|
e.
|
More
information is needed to answer this question.
|
If the equilibrium total pressure of
the system below is 1.0 atm in a 1.0 L flask, what is the partial pressure of N2O4?
N2O4 (g) → 2 NO2 (g) Kp = 0.660 at 319 K
N2O4 (g) → 2 NO2 (g) Kp = 0.660 at 319 K
a.
|
0.50 atm
|
b.
|
0.45 atm
|
c.
|
0.55 atm
|
d.
|
0.27 atm
|
e.
|
0.66 atm
|
The solubility of calcium chromate is
1.56 × 10¯3 g/100
mL of solution. What is the Ksp for
CaCrO4?
a.
|
2.4 × 10¯4
|
b.
|
1.5 × 10¯5
|
c.
|
7.6 × 10¯6
|
d.
|
1.0 × 10¯8
|
e.
|
< 1.0
× 10¯8
|
Which of the following is most likely
to precipitate Cl1- ions?
1.
|
NaCl(s) à Na1+(aq) + Cl1-(aq)
|
2.
|
PbCl2(s) à Pb2+(aq) + 2 Cl1-(aq)
Ksp =
1.75 ∗ 10-5
|
3.
|
AgCl(s) à Ag1+(aq) + Cl1-(aq)
Ksp =
1.8 ∗ 10-10
|
4.
|
Hg2Cl2(s) à 2 Hg1+(aq) + 2 Cl1-(aq) Ksp =
1.1 ∗ 10-18
|
At a certain temperature, Kp =
25 for the following reaction:
NH4Cl (s) ⇔ NH4 (g) + HCl (g)
What is the total pressure, in atm, of the gases at equilibrium?
What is the total pressure, in atm, of the gases at equilibrium?
a.
|
10
|
b.
|
5
|
c.
|
25
|
d.
|
6.3 × 102
|
e.
|
More
information is required.
|
Consider the solubility of BaSO4. If Ba(NO3)2 is
added to the solution, the solubility of the barium sulfate:
1.
|
increases
|
2.
|
is
unaffected
|
3.
|
is moot
because barium sulfate is a strong electrolyte
|
4.
|
decreases
|
HIn + H2O <=> In- + H3O+
If the HIn species is the "acid color" or clear for the phenolphthalein and the In- species is the "base color" or pink for this particular indicator, what color will appear in a flask in which a 0.2993 gram sample of KHP has been totaled neutralized with an excess of NaOH?
1.
|
the flask is pink
|
2.
|
the flask
is colorless
|
3.
|
there is
insufficient information to solve this problem
|
4.
|
the flask
is white from KCl precipitation
|
What is the value of Kb for
the formate anion, HCOO¯? Ka(HCOOH) = 2.1 × 10¯4
a.
|
2.1 × 10¯4
|
b.
|
-2.1 ×
10¯4
|
c.
|
6.9 × 10¯6
|
d.
|
4.8 × 10¯11
|
e.
|
2.1 × 10¯18
|
Use the following information to
calculate the solubility product constant, Ksp, for CuCl. A
saturated solution of CuCl in water was prepared and filtered. From the
filtrate, 1.0 L was measured out into a beaker and evaporated to dryness. The
solid CuCl residue recovered in the beaker was found to weigh 0.041g.
a.
|
Ksp =1.7 × 10¯9
|
b.
|
Ksp = 1.7 × 10¯7
|
c.
|
Ksp = 1.7 × 10¯5
|
d.
|
Ksp = 4.3 × 10¯4
|
e.
|
Ksp = 2.1 × 10¯2
|
Assuming that the total volume does not
change after 0.200 g of KCl is added to 1.0 L of a saturated aqueous solution
of AgCl, calculate the number of moles of Ag+ ion
in the solution after equilibrium has been reestablished. For AgCl, Ksp =
1.8 × 10¯10
a.
|
1.8 × 10¯10 mol
Ag+
|
b.
|
9.0 × 10¯10 mol
Ag+
|
c.
|
9.0 × 10¯9 mol
Ag+
|
d.
|
6.7 × 10¯8 mol Ag+
|
e.
|
1.3 × 10¯5 mol
Ag+
|
Which is not correct concerning equilibrium?
a.
|
The
concentration of reactants and products are no longer changing.
|
b.
|
Either
the reactants or the products of a reaction could be used to attain
equilibrium for a reversible reaction.
|
c.
|
The ratio
of the concentrations of products and reactants, raised to appropriate
powers, is a constant.
|
d.
|
The rates
of the forward and reverse reactions are the same.
|
e.
|
At equilibrium, the rates of the forward
and reverse reaction become zero.
|
The acid dissociation constant Ka equals
1.26 × 10¯2 for
HSO4¯
and is 5.6 × 10¯10 for
NH4+. Which statement
about the following equilibrium is correct?
HSO4¯(aq) + NH3(aq) ó SO42¯(aq) + NH4+(aq)
HSO4¯(aq) + NH3(aq) ó SO42¯(aq) + NH4+(aq)
a.
|
This
reaction is impossible to predict, since the strong acid and the weak base
appear on the same side of the equation.
|
b.
|
Neither
reactants nor products will be favored because all of the species are weak
acids or bases.
|
c.
|
The products will be favored because the
hydrogen sulfate ion is a stronger acid than the ammonium ion.
|
d.
|
The
reactants will be favored because ammonia is a stronger base than the sulfate
anion.
|
e.
|
The
initial concentrations of the hydrogen sulfate ion and ammonia must be known
before any prediction can be made.
|
Predict the effect of adding some HCN
on the reaction,
CH4(g) + NH3(g) ó HCN + 3 H2(g)
a.
|
Amount of CH4(g)
will increase
|
b.
|
Amount of
NH3(g) will decrease
|
c.
|
Amount of
H2(g) will increase
|
d.
|
Amount of
CH4(g) will stay the same
|
For the following reaction, which of
these changes would produce less CaCO3?
CO2(g) + Ca(OH)2(s) ó CaCO3(s) + H2O(l) DH = -113 kJ
a.
|
Decrease
temperature at constant pressure
|
b.
|
Increase volume at constant temperature
|
c.
|
Increase
the partial pressure of CO2
|
d.
|
Remove
half of the initial amount of CaCO3
|
e.
|
Nothing -
as it's a solid, CaCO3 is not involved in the reaction
|
At a certain temperature, the
equilibrium mixture of the reaction PCl5 (g)
⇔ PCl3 +
Cl2 (g) has PCl5 =
1.50 atm. PCl3 = 0.10 atm and PCl2 =
7.50 atm Calculate the value of Kp at
this temperature.
a.
|
0.77
|
b.
|
2.0
|
c.
|
1.0
|
d.
|
1.3
|
e.
|
0.50
|
If 1.00 mole of PCl3 and
1.00 mole of Cl2 are
placed in a 5.00-L container, the following equilibrium is reached.
PCl3 (g) + Cl2 (g) ⇔ PCl5 (g) Kc = 10.0 at the temperature maintained.
PCl3 (g) + Cl2 (g) ⇔ PCl5 (g) Kc = 10.0 at the temperature maintained.
What
is the equilibrium concentration of [PCl3] in mol/L?
a.
|
0.12
|
b.
|
0.13
|
c.
|
0.14
|
d.
|
0.11
|
e.
|
0.10
|
The solubility of silver chromate is
0.0287 g/1.0 L of solution. What is the Ksp for
Ag2CrO4?
a.
|
9.5 × 10¯5
|
b.
|
2.6 × 10¯12
|
c.
|
6.5 × 10¯13
|
d.
|
< 1.0
× 10¯13
|
e.
|
2.4 × 10¯5
|
A 1.25 M solution of the weak acid HA is 9.2%
dissociated. What is the pH of the solution?
a.
|
0.64
|
b.
|
0.94
|
c.
|
1.13
|
d.
|
2.16
|
e.
|
None of
these choices is correct.
|
Predict the effect of increasing the
container volume on the reaction,
CH4(g) + NH3(g) ó HCN + 3 H2(g)
a.
|
Amount of
CH4(g) will increase
|
b.
|
Amount of NH3(g)
will decrease
|
c.
|
Amount of
H2(g) will decrease
|
d.
|
Amount of
CH4(g) will stay the same
|
Hydrogen is produced industrially by
reacting propane and liquid water:
C3H8(g) + 3 H2O(l) --> 3 CO(g) + 7 H2(g)
If the numerator of the equilibrium expression is expressed as: [CO]m[H2]n, what are the values of "m" and "n"?
C3H8(g) + 3 H2O(l) --> 3 CO(g) + 7 H2(g)
If the numerator of the equilibrium expression is expressed as: [CO]m[H2]n, what are the values of "m" and "n"?
1.
|
2, 1
|
2.
|
1, 2
|
3.
|
7, 3
|
4.
|
3, 7
|
A 0.050 M solution of the weak acid HA has [H3O+] = 3.77 × 10¯4 M.
What is the Ka for
the acid?
a.
|
7.5 × 10¯3 M
|
b.
|
2.8 × 10¯6 M
|
c.
|
7.0 × 10¯7 M
|
d.
|
7.0 × 10¯8 M
|
e.
|
2.6 × 10¯11 M
|
A saturated solution of calcium
hydroxide, Ca(OH)2,
is in contact with excess solid Ca(OH)2. Which of the following statements
correctly describes what will happen when aqueous HCl (a strong acid) is added
to this mixture, and system returns to equilibrium? (For Ca(OH)2, Ksp =
6.5 × 10¯6)
a.
|
The
solubility of Ca(OH)2 will be unchanged.
|
b.
|
The OH¯ concentration will decrease and
the Ca2+ concentration
will increase.
|
c.
|
The OH¯
concentration will increase and the Ca2+ concentration will decrease.
|
d.
|
The
concentrations of both Ca2+ and OH¯ will increase.
|
e.
|
The
solubility of Ca(OH)2 will decrease.
|
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